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[求助] 请教kinematic constraint

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发表于 2007-6-14 02:10:40 | |阅读模式

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发表于 2007-6-14 06:55:58 |
TO define a node set for the right side, say RIGHT. make a reference node,(NSET=REF_RIGHT) which is not involved in the model. then, use:<br />*KINEMATIC COUPLING, REF NODE= REF_RIGHT.<br />RIGHT,&nbsp;&nbsp;1<br /><br />reference: 20.2.3-1:KINEMATIC COUPLING CONSTRAINTS ( V6.5)<br />Typical applications:

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发表于 2007-6-14 15:30:25 |
Typical applications:<br />&nbsp; &nbsp;&nbsp; &nbsp;&nbsp;&nbsp;The kinematic coupling constraints are useful in cases where a large number of nodes (the “coupling” nodes) are constrained to the rigid body motion of a single node and the degrees of freedom that participate in the constraint are selected individually in a local coordinate system. In many such cases MPCs either are not available or would have to be prescribed individually for each constrained node. A typical example is shown in Figure 28.2.3–1, where a kinematic coupling constraint is used to prescribe a twisting motion to a model without constraining radial motions. In other applications the kinematic coupling constraint can be used to provide coupling between continuum and structural elements.

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发表于 2007-6-14 17:22:28 |
谢谢你给我的回复.<br /><br />我现在还有两个问题请教:<br /><br />1,我想实现两个面,上边的面具有相同2方向的位移,右边的面具有相同1方向的位移,是否设置其中一个就可以?只设一个好像不可以,但是设置两个就遇到了以下的这个问题;<br /><br />2,两个面有一个共用点,设置两个时会出错;<br /><br />我可能考虑还是不周全,请您指教了,谢谢.

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发表于 2007-6-15 09:54:55 |
如果我设置两个,则出现以下的错误信息:1 nodes are missing degree of freedoms. The MPC/Equation/kinematic coupling constraints can not be formed. The nodes have been identified in node set ErrNodeMissingDofConstrDef.<br /><br />如果我只设一个,不能达到我的目的,得到的位移分布图如下:<br />1方向:

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发表于 2007-6-15 15:29:15 |
I have met the same problem. I just remove the over constrained node from the coupling set. I am also a beginner for Abaqus. In fact, I'm not sure if kinematic is available for this kind of problem.

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发表于 2007-6-16 04:18:15 |
好像不可以。我是在文献中看到用kinematic constraint的。<br />是否还有其他方法可以达到这个目的?<br />向大家求教了。

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发表于 2007-6-17 03:49:00 |
问题已解决! <br />只要设置边界位移就可以了<br />终于解决了,很简单,但是困扰自己很久.希望后来人不会有这个困惑了.
 
 
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